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Let the length of the first train is x metre Length of second train = 3x/4 Therefore, (66 + 42) x 5/18 = {x + (3x/4)}/28 ⇒ 108 x 5/18 = (7x/4)/28 ⇒ x = 480 m Therefore, let the length of the platform be y metre ⇒ 66 x 5/18 = (480 + y)/36 ⇒ 660 = 480 + y ⇒ y = 660 – 480 = 180 m
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