Train P travelling at 66 km/hr crosses another train Q, having three fourth of its length and travelling in opposite direction at 42 km/hr in 28 seconds. Train P passed a railway platform in 36 seconds. Find the length of platform.
Let the length of the first train is x metre Length of second train = 3x/4 Therefore, (66 + 42) x 5/18 = {x + (3x/4)}/28 ⇒ 108 x 5/18 = (7x/4)/28 ⇒ x = 480 m Therefore, let the length of the platform be y metre ⇒ 66 x 5/18 = (480 + y)/36 ⇒ 660 = 480 + y ⇒ y = 660 – 480 = 180 m
14.12 × 21.98 + 25.22% of 195.99 = ? × 50.9
25.19% of (?2 ÷ 38.87 × 4679.94) = 6299.82 ÷ 419.78 × 50.15
36.22 of 249.98% + 299.99 ÷ 30.18 = ?
26.11 × 7.98 + 27.03 × 3.12 – 34.95 + 93.9 × 3.02 =?
What is the value of "π"
25.22% of (59.9 × 4.01) + 69.97 =?
80.22 of 149.98% + 459.99 ÷ 23.18 = ?
√323.89 × (3.20) ÷ 9.02 =?
21% of 6600 + 453.987 =?
? + 39.99 X 3.01 = √624.99 X 10.01% of 49.99