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Speed of the first train = [120/15] m/sec = 8 m/sec Speed of the second train = [120/30] m/sec = 4 m/sec Speed = (8 + 4) m/sec = 12 m/sec Required time = (120 + 120)/12 sec = 20 sec
128 ÷ 22 × ? = 15% of 300 ÷ 9
(√1024 + √324)% of 780 = ?% of 260
∛21952 × 44 = ? × 14
154 × 7 + 480 × 5 = ?% of 6956
[(1245 ÷ 9) ÷ 12] × 540 = ?2 – 175
√(24 × 5 ÷ ?) × 4 = 56 + 34 – 10
Find the simplified value of the given expression.
(1/4) of {64 - 28 x 15 + 13 x 16 - 12.5 of 122}
[(√ 529) + 67] x 5 = ?
? % of 1200 = 20% of 30% of 3600
1220 ÷ 61 ÷ 5 + 450 of 20% - 70 = √ ?