Car 'X' travels for 4 hours to reach from point A to B. Car 'Y' travels 210 km to reach from point B to C in 3 hours. Distance travelled by car 'X' to cover A to B is one seventh more than distance travelled by car 'Y'. How much time will car 'X' takes to reach from point A to point C?
Time taken by X to reach from point A to B = 4 hrs Distance travelled by Y in 3 hours to reach from point B to C = 210 km Speed of Y = 210/3 = 70 kmph Distance from point A to B = 210 + 210 × 1/7 = 240 km Speed of X = 240/4 = 60 kmph Therefore, Time taken by X to reach from point A to C = (240 + 210)/60 = 450/60 = 7.5 hrs
14.12 × 21.98 + 25.22% of 195.99 = ? × 50.9
25.19% of (?2 ÷ 38.87 × 4679.94) = 6299.82 ÷ 419.78 × 50.15
36.22 of 249.98% + 299.99 ÷ 30.18 = ?
26.11 × 7.98 + 27.03 × 3.12 – 34.95 + 93.9 × 3.02 =?
What is the value of "π"
25.22% of (59.9 × 4.01) + 69.97 =?
80.22 of 149.98% + 459.99 ÷ 23.18 = ?
√323.89 × (3.20) ÷ 9.02 =?
21% of 6600 + 453.987 =?
? + 39.99 X 3.01 = √624.99 X 10.01% of 49.99