Two trains A and B started from a point and running perpendicularly. if the speed of train A and train B is 3.5 km/hr and 12 km/hr respectively, find the distance between them after 2 hours.
Speed1 = 3.5 km/h Speed2 = 12 km/h Distance, d1 = 3.5 × 2 = 7 km Distance, d2 = 12 × 2 = 24 km As, both are running perpendicularly Hence, the required distance = √(d12 + d22) = √(72 + 242 ) = √(49 + 576) = √625 = 25 km
I. 2y2- 37y + 143 = 0
II. 2x2+ 15x – 143 = 0
I.8(x+3)+ 8(-x)=72
II. 5(y+5)+ 5(-x)=150
I. x2 – 13x + 40 = 0
II. 2y2 – 15y + 13 = 0
I. (2x-3)3+ 1/((2x-3)³)=2
II. 4y²+(y+8)^2= 157
I. 17x² - 26x – 16 = 0
II. 17y²- 26y + 9 = 0
I. 20y² - 13y + 2 = 0
II. 6x² - 25x + 14 = 0
I. 6x2 + 23x + 10 = 0
II. 2y2 - 3y - 5 = 0
I. 3x2 – 16x + 21 = 0
II. y2 – 13y + 42 = 0
I. 2y2 + 31y + 99 = 0
II. 4x2 + 8x – 45 = 0
I. 2x2– 5x – 63 = 0
II. 2y2– 7y – 72 = 0
