A train started from station P and preceded towards station Q at a speed of 54 km/h. 40 minutes later, another train started from station Q and preceded towards station P at 100 km/h. If the distance between the two stations is 806 km, at what distance from station P will the trains meet?
Let the train will meet ‘t’ hours after the train from station Q started Distance travelled by train started from station P = 54 x 40/60 km Distance travelled by train started from station Q = (54 + 100) x t km Total distance between station P and Q = 806 km Now, 54 x (40/60) + (54 + 100) x t = 806 ⇒ 40 + 154t = 806 ⇒ 154t = 806 – 40 = 770 ⇒ t = 770/154 = 5 hours Distance travelled by train starting from station P at all meeting point = 36 + 54 x 5 = 306 km
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