A 440 m long train crosses a platform twice its length in 2 min. Find the speed of the train.
Speed of train = (Length of train + Length of Platform)/Required time Length of train = 440 m Crossing time of platform = 2 × 60 = 120 sec Length of platform = 440 × 2 = 880 m Let the speed of train be x. Speed of train = (440 + 880)/120 ⇒ x = 11 m/s
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DSL stands for