Question
Two trains of same length are running in parallel tracks
in the same direction with speed 61 km/hr and 115 km/hr respectively. The latter completely crosses the former in 20 seconds. Find the length of each train (in m).Solution
When two trains cross each other, they cover distance equal to the sum of their lengths with relative speed. Let's take length of each train = x So, total length of both trains = 2x Relative speed = (115 – 61) × (5/18) = 15 m/sec. ∴ Total length = Time × Relative speed ⇒ 2x = (20 × 15) ⇒ x = 150 m
15% of 695 – 12.5% of 250 =? – 1200
`2(1/3)` + `4(1/4)` + `4(2/3)` + `8(7/6)` + ? = `4(3/5)xx4(1/2)`
...36895 - 4256 - 2233 = ?
Find the simplified value of the given expression:
15 of 4 ÷ 3 × 4² + √49 – 1223% of 8040+ 42% of 545 = ?%of 3000
1300% of 2341 + 1200% of 6321 = ?
150% of 84 + ?% of 130 = 230
Find the Value of √(-√3+√(3+8√(7+4√3)))?
1780 – 60 ÷ 4 x 80 = ?
If A = 0.84181818... then what will be the difference between the numerator and denominator of the lowest fraction form of A?
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