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Total distance covered by train in 48 seconds with the speed of 120 km/hr. Distance = 120 km/hr × 48 sec = 120 × 5/18 × 48 = 1600 metres. Length of train + length of platform = 1600 metres 600 + length of platform = 1600 Length of platform = 1000 m
I: x2 + 31x + 228 = 0
II: y2 + 3y – 108 = 0
I. 3p² - 17p + 22 = 0
II. 5q² - 21q + 22 = 0
I.12a2– 55a + 63 = 0
II. 8b2- 50b + 77 = 0
...I. 27x6-152x3+125=0
II. 216y6 -91y3+8=0
If a and b are the roots of x² + x – 2 = 0, then the quadratic equation in x whose roots are 1/a + 1/b and ab is
Solve the quadratic equations and determine the relation between x and y:
Equation 1: x² - 40x + 375 = 0
Equation 2: y² - 36y + 324 = 0
Solve the quadratic equations and determine the relation between x and y:
Equation 1: x² - 42x + 392 = 0
Equation 2: y² - 46y + 480 = 0
I. 2x² - 9x + 10 = 0
II. 3y² + 11y + 6 = 0
Solve the quadratic equations and determine the relation between x and y:
Equation 1: x² - 32x + 207 = 0
Equation 2: y² - 51y + 648 = 0
I. 10p² + 21p + 8 = 0
II. 5q² + 19q + 18 = 0
