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Let the length of train ‘A’ be ‘x’ metres Therefore, length of the goods train = ‘4x’ metres Speed of train ‘A’ = 126 × (5/18) = 35 m/s According to the question, 4x + x = 35 × 25 => 5x = 875 => x = 175 Therefore, time taken by train ‘B’ to cross train ‘A’ = {(175 + 500)/(35 + 10)} = 15 seconds
25% of 140 + 2 × 8 = ? + 9 × 5
√144 × √121 + 25% of 600 = ? + 256
45% of 360 - 160 + ? = √324
1360 ÷ 8 + 490 ÷ √49 + ? = 150 × 2
What is the value of (6 + 4) ×12/4 + 5 – 3?
1000÷ 250 = ( 3√? × √1444) ÷ ( 3√512 × √361)
78.89 × 81.03 – (16.83)² + 8.33% of 9602.87 = ? – 50.23
√( (664+ √(136+ √(59+ √(21+ √(7+ √81) ) ) ) ) ) = ?
150% of ? + 280 ÷ 35 = 132 - 122 + 7