Question
Train βAβ running with a speed of 126 km/hr can
cross a standing goods train of 4 times its length in 25 seconds. Find the time taken by 500 metres long train βBβ which is coming from opposite direction of train βAβ, with a speed of 10 m/s, to cross train βAβ.Solution
Let the length of train βAβ be βxβ metres Therefore, length of the goods train = β4xβ metres Speed of train βAβ = 126 Γ (5/18) = 35 m/s According to the question, 4x + x = 35 Γ 25 => 5x = 875 => x = 175 Therefore, time taken by train βBβ to cross train βAβ = {(175 + 500)/(35 + 10)} = 15 seconds
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