Train ‘A’ running with a speed of 63 km/hr can cross a standing goods train of 4 times its length in 24 seconds. Find the time taken by 150 metres long train ‘B’ which is coming from opposite direction of train ‘A’, with a speed of 15 m/s, to cross train ‘A’.
Let the length of train ‘A’ be ‘x’ metres Therefore, length of the goods train = ‘4x’ metres Speed of train ‘A’ = 63 × (5/18) = 17.5 m/s According to the question, 4x + x = 17.5 × 24 => 5x = 420 => x = 84 Therefore, time taken by train ‘B’ to cross train ‘A’ = {(84 + 150)/(24 + 15)} = 6 seconds
I. p2 - 19p + 88 = 0
II. q2 - 48q + 576 = 0
I. 20x² - 93x + 108 = 0
II.72y² - 47y - 144 = 0
I. 2x2– 25x + 33 = 0
II. 3y2+ 40y + 48 = 0
I. 27x6- 152x3+ 125 = 0
II. 216y6- 91y3+ 8 = 0
I.√(3x-17)+ x=15
II. y+ 135/y=24
I. 8a2 – 22a+ 15 = 0
II. 12b2 - 47b + 40=0
In each of these questions, two equations (I) and (II) are given.You have to solve both the equations and give answer
I. x2 – ...
I. 27x6-152x3+125=0
II. 216y6 -91y3+8=0
I. x2 - 20x + 96 = 0
II. y2 - 23y + 22 = 0
I. y² - 7 y – 18 = 0
II. x² + 10 x + 16 = 0