Question
Two trains βAβ and βBβ started from station
βPβ and βQβ towards station βQβ and βPβ respectively at the same time. When they met after 10 hours, train βBβ has travelled 102 km more than train βAβ. Find the distance travelled by train βAβ in 6 hours if distance between both stations is 602 km.Solution
Let distance travelled by train βAβ at the time of meet = βxβ km So, distance travelled by train βBβ at the time of meet = βx + 102β km According to question; x + x + 102 = 602 => 2x = 500 => x = 250 Distance travelled by train βAβ in 10 hours = 250 km Speed of train βAβ = 250/10 = 25 km/h Distance travelled by train βAβ in 6 hours = 25 Γ 6 = 150 km
Without stopping the speed of the train is 150 kmph, with stopping the speed of the train is 80 kmph.Find the stop time of the train?
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