Question
Two trains βAβ and βBβ started from station
βPβ and βQβ towards station βQβ and βPβ respectively at the same time. When they met after 9 hours, train βBβ has travelled 130 km more than train βAβ. Find the distance travelled by train βAβ in 12 hours if distance between both stations is 184 km.Solution
Let distance travelled by train βAβ at the time of meet = βxβ km So, distance travelled by train βBβ at the time of meet = βx + 130β km According to question; x + x + 130 = 184 => 2x = 54 => x = 27 Distance travelled by train βAβ in 9 hours = 27 km Speed of train βAβ = 27/9 = 3 km/h Distance travelled by train βAβ in 12 hours = 12 Γ 3 = 36 km
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