A 400 m long train crosses a platform twice its length in 2 min. Find the speed of the train.
Speed of train = (Length of train + Length of Platform)/Required time Length of train = 400 m Crossing time of platform = 2 × 60 = 120 sec Length of platform = 400 × 2 = 800 m Let the speed of train be x. Speed of train = (400 + 800)/120 ⇒ x = 1200/120 = 10 m/s
14.12 × 21.98 + 25.22% of 195.99 = ? × 50.9
25.19% of (?2 ÷ 38.87 × 4679.94) = 6299.82 ÷ 419.78 × 50.15
36.22 of 249.98% + 299.99 ÷ 30.18 = ?
26.11 × 7.98 + 27.03 × 3.12 – 34.95 + 93.9 × 3.02 =?
What is the value of "π"
25.22% of (59.9 × 4.01) + 69.97 =?
80.22 of 149.98% + 459.99 ÷ 23.18 = ?
√323.89 × (3.20) ÷ 9.02 =?
21% of 6600 + 453.987 =?
? + 39.99 X 3.01 = √624.99 X 10.01% of 49.99