When two trains cross each other, they cover distance equal to the sum of their lengths with relative speed. Let's take length of each train = x So, total length of both trains = 2x Relative speed = (100 – 40) × (5/18) = 50/3 m/sec. ∴ Total length = Time × Relative speed ⇒ 2x = (27 × 50)/3 ⇒ x = 225 m
116*2/3% of 18600 + 666*2/3% of 1290 = 457*1/7% of 1750 + 555*5/9% of 3150 + ?
?2 = √20.25 × 10 + √16 + 32
242 + 80% of 1620 = ? × 16 – 35% of 800
(750 / 15 × 15 + 152 + 20% of 125) = ?3
7/11 × 1034 + 1(4/7) × 2401 = 1230 +?
4(1/3) × 2(11/14) = 50% of ? + 86/11
32% of 4080 + 24% of 455 = x% of 4000
12 × 19 + 13 × 15 + 152 = ?% of 500
