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Length of smaller train = 450 metre Speed of smaller train = 99 × (5/18) = 27.5 m/s Length of bigger train = 555 metres Speed of bigger train = 90 × (5/18) = 27.5 m/s Since, the smaller train is completely obscured by larger train, therefore, extra length of larger train = 555 – 450 = 105 metres Relative speed of trains ‘A’ and ‘B ‘= 27.5 + 25 = 52.5 m/s (Since, the trains are running in opposite direction) Required time = 105/52.5 = 2 second
Find the maximum people that a company can recruit, if the recruit function is given by p(x) = 41 − 24x − 18x2
If 3.5 are the Eigen values of a square matrix A of order 2. then the Eigen values of the matrix A3 will be:
Find the maximum value of the function g(x) = 4x3 − 24x2 + 48x – 10 on the set T = {x ∈ R ∣ x2 − 14x + 45 ≤...