Question
Train βAβ can cross a pole in 6 seconds and a 90
metre long platform in 12 seconds. If the ratio of length of train βAβ and train βBβ is 2:5, respectively, then find the time taken by train βBβ to cross a pole with a speed of 25 m/s.Solution
Let the length and speed of the train βAβ be βlβ metre and βsβ m/s, respectively. According to question, l = 6s Also, 12s = 6s + 90 Or, 6s = 90 Or, s = 15 Therefore, length of train βAβ = 6s = 90 metres Length of train βBβ = 90 Γ (5/2) = 225 metres Required time taken = 225 Γ· 25 = 9 second
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