Question
Train ‘A’ can cross a pole in 10 seconds and a 140
metre long platform in 12 seconds. If the ratio of length of train ‘A’ and train ‘B’ is 2:5, respectively, then find the time taken by train ‘B’ to cross a pole with a speed of 20 m/s.Solution
Let the length and speed of the train ‘A’ be ‘l’ metre and ‘s’ m/s, respectively. According to question, l = 10s Also, 12s = 10s + 140 Or, 2s = 140 Or, s = 70 Therefore, length of train ‘A’ = 10s = 700 metres Length of train ‘B’ = 140 × (5/2) = 1750 metres Required time taken = 1750 ÷ 20 = 87.5 second
The respective normal account balances of Sales, Sales Returns and Allowances, and Sales Discounts are?
How many digits are there in a MMID code used for money transfer through mobile devices?
ICDS III deals with which of the following:
Under what heading, "uncalled liability on partly paid up shares" will appear while preparing final accounts of limited liability companies?
Which of the following is NOT an advantage of Bonus issue by a company?
A type of market where debt and stocks are traded and maturity period is more than a year is known as
A company faces a lawsuit for patent infringement. Legal advisors state a 55% probability of losing with damages of ₹50 crore, but range could be ₹4...
If the MOS = 40000 units and BE units are 35000 and PV ratio is 60%. Calculate profit if revenue per unit is 8.
Shortage in material can be due to normal reasons or due to abnormal reasons.
Which of the following will be regarded as shortage due to abnormal reason?
ABC Ltd. offers its existing shareholders the right to buy one share for every four held at ₹100 when the current market price is ₹150. What is the ...
