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Speed of train ‘A’ = {(100 + 50)/20} = (150/20) = 7.5 m/s Speed of train ‘B’ = 7.5 + 6 = 13.5 m/s = 13.5 × (18/5) = 48.6 km/hr Required distance travelled by train ‘B’ = 48.6 × 5 = 243 km
1120 / √x = 80 Then x = ?
116 ÷ 280 of 1/2 + 3/5 × 5/3 = ?
65% of ? = 50 + 20 × 4
Simplify the following questions:
(11) 8.5 × (121) 5.5 ÷ (1331) 5.5 = (11) ?
...17% of 250 + ? = 108
72 + 122 - 25% of 600 = ?
40 × 5 + 27) × 9 = ?
10% of 80% of 50% of ? = 4
Find the simplified value of the given expression:
(12 ÷ 3 of 2 + 11 of 2) ÷ 4
[(√576 × √144) ÷ √1296]2 = ? ÷ 3