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Let the distance travelled by slower train be ‘x’ km So, distance travelled by faster train = ‘x + 122’ km ATQ, (x/50) = {(x + 122)/60} Or, 60x = 50x + 6100 Or, 10x = 6100 So, x = 610 Total distance between station ‘A’ and station ‘B’ = (610 + 610 + 122) = 1342 km
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