Two trains started from stations ‘A’ and ‘B’ at same time and started travelling towards each other at speeds of 60 km/hr and 50 km/hr, respectively. At the time of their meeting, the faster train has travelled 122 km more than the slower train. Find the distance between the stations ‘A and ‘B’.
Let the distance travelled by slower train be ‘x’ km So, distance travelled by faster train = ‘x + 122’ km ATQ, (x/50) = {(x + 122)/60} Or, 60x = 50x + 6100 Or, 10x = 6100 So, x = 610 Total distance between station ‘A’ and station ‘B’ = (610 + 610 + 122) = 1342 km
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