Two trains started from stations ‘A’ and ‘B’ at same time and started travelling towards each other at speeds of 66 km/hr and 56 km/hr, respectively. At the time of their meeting, the faster train has travelled 115 km more than the slower train. Find the distance between the stations ‘A and ‘B’.
Let the distance travelled by slower train be ‘x’ km So, distance travelled by faster train = ‘x + 115’ km ATQ, (x/56) = {(x + 115)/66} Or, 66x = 56x + 6440 Or, 10x = 6440 So, x = 644 Total distance between station ‘A’ and station ‘B’ = (644 + 644 + 115) = 1403 km
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