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    Question

    Train B which is ‘d’ meter long can cross a pole in

    35 seconds. Train A can cross a platform of (d+10) meter long in (t+45) seconds. The ratio between the lengths of train A and B is 9:7 respectively. Train B can cross train A in (3t-70) seconds.If the difference between the speeds of both trains is 4 m/s, then find out the value of ‘t’.
    A 80 Correct Answer Incorrect Answer
    B 120 Correct Answer Incorrect Answer
    C 100 Correct Answer Incorrect Answer
    D 60 Correct Answer Incorrect Answer
    E Cannot be determined Correct Answer Incorrect Answer

    Solution

    Let’s assume the speeds of train A and B are ‘Sa‘ and ‘Sb‘ respectively.

    The ratio between the lengths of train A and B is 9:7 respectively.

    Let’s assume the lengths of train A and B are 9y and 7y respectively.

    Train B which is ‘d’ meter long can cross a pole in 35 seconds.

    So d = 7y

    7y = 35xSb

    y = 5xSb   Eq.(i)

    Train A can cross a platform of (d+10) meter long in (t+45) seconds.

    (7y+10) = (t+45)xSa   Eq.(ii)

    Train B can cross train A in (3t-70) seconds. If the difference between the speeds of both trains is 4 m/s.

    (9y+7y)/(3t-70) = 4

    16y = 4(3t-70)

    4y =(3t-70)   Eq.(iii)

    In Eq.(i), Eq.(ii) and Eq.(iii), there are a total of four variables. We cannot determine the value of ‘t’ from the given information.

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