Question
Train βAβ of length 150 metres crosses a platform of
length 250 meters in 20seconds. If the ratio of the speed of train βAβ to that of train βBβ is 5:7, then find (1/5)th of the length (in metres) of train βBβ given that train βBβ can cross a pole in 10 seconds.Solution
Speed of train βAβ = {(150 + 250)/20} = 400/20 = 20 m/s Speed of train βBβ = (7/5) Γ 20 = 28 m/s Length of train βBβ = 28 Γ 10 = 280 metres (1/5)th of length of train βBβ = (1/5) Γ 280 = 56 metres
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