Train ‘A’ of length 150 metres crosses a platform of length 250 meters in 20seconds. If the ratio of the speed of train ‘A’ to that of train ‘B’ is 5:7, then find (1/5)th of the length (in metres) of train ‘B’ given that train ‘B’ can cross a pole in 10 seconds.
Speed of train ‘A’ = {(150 + 250)/20} = 400/20 = 20 m/s Speed of train ‘B’ = (7/5) × 20 = 28 m/s Length of train ‘B’ = 28 × 10 = 280 metres (1/5)th of length of train ‘B’ = (1/5) × 280 = 56 metres
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