Question
A train crosses a bridge in 15 secs while it crosses a
man standing on a platform in 8 secs. If the speed of train 108 km/hrs, then what will be the time taken by the train to cross a tunnel whose length is 210 meters more than the length of the bridge .Solution
ATQ, we can say that Speed of train is = (108 x 5)/18 = 30 m/s then, the Length of bridge is = 30 x 7 = 210 m {The "30 × 7" step comes from: Extra time over bridge = 15 − 8 = 7 sec = Bridge length = 30×7 = 210 m} then, the Length of tunnel = 210 + 210 = 420 m Length of train 108 × 5/18 = (x + 210)/15 30 × 15 = x + 210 x = 240 meter therefore, the Required time = (240 + 420)/30 = 22 seconds
I. 2x2 - 9 x + 9 = 0
II. 2y2 - 7 y + 3 = 0
In the question, two equations I and II are given. You have to solve both the equations to establish the correct relation between 'p' and 'q' and choose...
I. 2x² - 15x + 13 = 0
II. 3y² - 6y + 3 = 0
I. x²= 961
II. y= √961
If a quadratic polynomial y = ax2 + bx + c intersects x axis at a and β, then
I. 27x6-152x3+125=0
II. 216y6 -91y3+8=0
I. 4x² - 21x + 20 = 0
II. 8y² - 22y + 15 = 0
Solve the quadratic equations and determine the relation between x and y:
Equation 1: 3x² + 6x - 9 = 0
Equation 2: 2y² - 16y + 32 = 0
I. 3p² + 13p + 14 = 0
II. 8q² + 26q + 21 = 0
I. 24x² - 58x + 23 = 0
II. 20y² + 24y – 65 = 0
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