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Let the speed of train C be ‘x’ km/hr. Then, speed of train D = (x + 21) km/hr Time = 3 hours 40 minutes = 3(40/60) = 3(2/3) = 11/3 hrs According to the question, => Speed = Distance/ Time => (x + x + 21) = 495/(11/3) => 2x + 21 = 45 × 3 => 2x = 135 - 21 => x = 57 Speed of train C = x = 57 km/hr Speed of train D = (x + 21) = 78 km/hr
(23.99)2– (17.99)2+ (1378.88 + 44.88) ÷ ? = 607.998
8.992 + (5.01 × 4.98) + ? = 224.03
14.12 × 21.98 + 25.22% of 195.99 = ? × 50.9
? = 49.99² ÷ (1.98⁵ + 8.01 × 89.91) + 75.15% of (263.89 × 49.11)
10.10% of 999.99 + 14.14 × 21.21 - 250.25 = ?
960.11 ÷ 23.98 × 5.14 – 177.9 = √?
? = 65.78² ÷ (5.01⁵ + 7.02 × 33.33) + 33.33% of (290.88 × 23.09)
? = 49.97% of 38.09% of 1998.95