Question
Two trains C and D started from point A and B
respectively. Speed of train D is 21 km/hr more than that of train C. Total distance between point A and B is 495 km. If both the trains meet in 3 hours 40 minutes, then find the speed of train D (in km/hr).Solution
Let the speed of train C be ‘x’ km/hr. Then, speed of train D = (x + 21) km/hr Time = 3 hours 40 minutes = 3(40/60) = 3(2/3) = 11/3 hrs  According to the question, => Speed = Distance/ Time => (x + x + 21) = 495/(11/3) => 2x + 21 = 45 × 3 => 2x = 135 - 21 => x = 57 Speed of train C = x = 57 km/hr Speed of train D = (x + 21) = 78 km/hr
What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)...
239.977 ÷ 5.998 + √840.913 × 6.113 = ? + 117.948
{(22.22 2 + 6.06 3 ) ÷ 15.15} × 3.03 = ? – 55.05 × 4.04
2√574 + 19.956% of 1449.978 = ?% of 628.08
What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)...
What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)...
499.99 + 1999 ÷ 39.99 × 50.01 = ?
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
630.11 ÷ 20.98 × 5.14 – 125.9 = √?Â
111.89 × 4.12 – 504.04 ÷ 2.12 = 170.12 + ?
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