The ratio between the speeds of train J and K is 7:5 respectively. Let’s assume the speed of train J and K is 7y and 5y respectively. Train J which is (a+140) metre long can cross a pole in 24 seconds. (a+140)/24 = 7y (a+140) = 168y Eq.(i) If train K can cross a man in 28 seconds. Let’s assume the length of train K is ‘k’. k/5y = 28 k = 140y Eq.(ii) It is assumed that both of the trains cross each other in (77/3) seconds. [(a+140)+k]/(7y+5y) = (77/3) [(a+140)+k]/(12y) = (77/3) Put Eq.(i) and Eq.(ii) in the above equation. [168y+140y]/(12y) = (77/3) (308y)/(12y) = (77/3) (77/3) = (77/3) We cannot obtain anything from the given information in the question. So the answer cannot be determined.
Find the simplified value of the following expression:
62 + 122 × 5 - {272 + 162 - 422}
18 × √225 + 378 ÷ √441 = ? × 9
Train M, ‘x’ metres long crosses (x – 30) metres long platform in 22 seconds while train N having the length (x + 30) metres crosses the same plat...
(2197)1/3 + (18)2 − 121 = ? − 69 × 5
{(5/8) + (4/5)} × (?/19) = 33
24.5% of 400 + 528 of 12.5 ÷ 11
Simplify the expression -:
17% of 250 + ? = 108
?2 = √20.25 × 10 + √16 + 32
25639 – 5252 – 3232 = ?