Length of train X = 40 × 54 × (5/18) = 600 m Length of train Y = (600/2) × 1 = 300 m => t = (600 + 300)/[(54 + 90) ×(5/18)] = 22.5 sec Required value = (t + 11) = 22.5 + 11 = 33.5
Statements:
Q ≥ R = P; R > S ≥ Z; S ≥ B < C
Conclusions:
I. C > Z
II. B < Q
Statements: V > U = T ≤ S; T > Z > L; L = N ≥ O
Conclusions:
I. V > L
II. O < S
III. T > V
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Some Trains are bus.
Only few buses are bike.
Only cycles are bike.
No cycle is plane.
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No sharpener is pencil.
All pencils are books.
Only a few pencils are bright.
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Only Doctor are Dancer.
Only a few Doctor are Painter.
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Statement:
No one is two.
A few two are three.
Only one is four.
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