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ATQ, Let, length of train be ‘d’ meter S = d/t So, 45 × (5/18) = d/36 d = 450 meter Length of the train = 450 meter 45 × (5/18) = (450 + 600)/t 12.5 = 1050/t t = 84 seconds
(129.98% of 8460) + (119.899% of 8640) = (130.009% of 15820) + ?
(29.97%) of 9840 + ? + (45.17% of 1240) = (31.955% of 11750)
15.78% of (287 + 302) + 12³ = ?% of 170 + 8 × 14 + 3²
If the difference between the compound interest (compounded annually) and the simple interest accrued over two years at a rate of...
599.9 - ? + 64.9 = (5% of 300.012) × 10.032
30.05% of 360.05 – 25.15% of 99.99 × 3.02 = ?
11.232 + 29.98% of 599.99 = ? × 6.99
19.22 × 11.99 + 142.15 = ?
(34.03 + 101.98) ÷ 17.211 = 89.9 – 25.23% of ?
16.22 × 12.99 + 142.15 = ?