Question
A high-speed Bullettrain takes 20 seconds to cross a
platform. The length of the Bullettrain is 40% less than the length of the platform. If the Bullettrain's speed is increased by 25%, what will be the time taken by the train to cross a pillar?Solution
ATQ, Let the length of the platform be '10a' metres So, length of the train = 10a × 0.6 = '6a' So, speed of the train = {(6a + 10a)/20} = '0.8a' m/s So, new speed of the train = 0.8a × 1.25 = 'a' m/s So, required time = 6a ÷ a = 6 seconds
Uttar pradesh , India, Asia
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