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Given- speed of A = 81km/h, distance of B = 600m Let speed of B = B, and distance of A = x When both the trains are running in the same direction (A – B) × 72 = x + 600 5/18 (81 – B) × 72 = x + 600 ... (1) When both the trains are running in the opposite direction 5/18 (81 + B) × 36 = x + 600 ... (2) From (1) and (2) 5/18 × (81 – B)72 = (81 + B) 36 ×5/18 81 × 2 – 2B = 81 + B 3B = 81 B = 27 Put the value of B in (1) (81 – 27) × 72 × 5/18 = x + 600 1080 – 600 = x x= 480 m
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