New Enroll here to Join NaBFID Analyst Into Class on May 6

    Question

    Train A takes 24 seconds to cross a pole and 20sec to

    cross a man walking at the speed of 5.6 meter per second towards it. Train B travels 1 meter per second slower than train A and takes 25%. Less time than train need to cross a pole. If the speed of train B had been 7 meter per second less than the time taken by it to cross 114-meter-long platform is ‘5a’. Find the value of ‘a’.
    A 3 Correct Answer Incorrect Answer
    B 5 Correct Answer Incorrect Answer
    C 6 Correct Answer Incorrect Answer
    D 8 Correct Answer Incorrect Answer
    E 9 Correct Answer Incorrect Answer

    Solution

    Let the speed of the train A = y m/s Then the length of train ‘A’= 24*y = 24y mt. Relative speed of train A wrt man = (y+5.6) m/s Also length of the train A = (y+5.6)*20 = (20y+112) mt. So, 24y = 20y+112 Y=28  Speed of train A is 28 m/s. Speed of train B = 28-1 = 27m/s. Time taken by Train ‘B’ to cross pole = 24*0.75 = 18 sec So length of train ‘B’ = 18*27 =486mt. New speed of train ‘B’ = 27-7 = 20m/s Required time taken ‘B’ = (486+114)/20 = 30 seconds 5a=30sec a=6

    Practice Next