Train 'P' starts its journey from a point at 6:00 pm, traveling at an average speed of 48 km/h. Train 'Q' departs from the same point towards Train 'P' two hours later at an average speed of 60 km/h. After traveling for 't' hours, Train 'Q's average speed reduces by 10% due to fog. If Train 'Q' and Train 'P' meet at 8:00 am, calculate the value of 't'.
ATQ, Train 'Q' started its journey 2 hours after Train 'P', i.e., at 8:00 pm. Lead of Train 'P' over Train 'Q' when Train 'Q' started its journey = 48 × 2 = 96 kms Train 'Q' meets Train 'P' at 8:00 am. Total time in which Train 'Q' meets Train 'P' = 12 hours ATQ, (60 - 48) × t + (54 - 48) × (12 - t) = 96 Or, 12 × t + 6 × (12 - t) = 96 Or, 12t + 72 - 6t = 96 Or, 6t = 96 - 72 Or, 6t = 24 Or, t = (24/6) So t = 4
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