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ATQ, Train 'Q' started its journey 2 hours after Train 'P', i.e., at 8:00 pm. Lead of Train 'P' over Train 'Q' when Train 'Q' started its journey = 48 × 2 = 96 kms Train 'Q' meets Train 'P' at 8:00 am. Total time in which Train 'Q' meets Train 'P' = 12 hours ATQ, (60 - 48) × t + (54 - 48) × (12 - t) = 96 Or, 12 × t + 6 × (12 - t) = 96 Or, 12t + 72 - 6t = 96 Or, 6t = 96 - 72 Or, 6t = 24 Or, t = (24/6) So t = 4
128 ÷ 22 × ? = 15% of 300 ÷ 9
(√1024 + √324)% of 780 = ?% of 260
∛21952 × 44 = ? × 14
154 × 7 + 480 × 5 = ?% of 6956
[(1245 ÷ 9) ÷ 12] × 540 = ?2 – 175
√(24 × 5 ÷ ?) × 4 = 56 + 34 – 10
Find the simplified value of the given expression.
(1/4) of {64 - 28 x 15 + 13 x 16 - 12.5 of 122}
[(√ 529) + 67] x 5 = ?
? % of 1200 = 20% of 30% of 3600
1220 ÷ 61 ÷ 5 + 450 of 20% - 70 = √ ?