ATQ, ATQ, S = D/t 54 × 5/18 = D/25 D = 15 × 25 = 375 Length of the train = 375 m Length of the platform = 375/5 × 2 = 150 m Time taken by train to cross the platform = (375 + 150)/(54 × 5/18) = 525/15 = 35 seconds Alternate solution: Time taken by train to cross the platform = 25 × (5 + 2)/5 = 35 seconds
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