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ATQ, Speed of train 'C' = 300/10 = 30 m/s Speed of train 'D' = 3×30 = 90 m/s Relative speed = 30+90 = 120 m/s Total distance covered by train 'D' in 12 seconds = 120×12 = 1440 meters Length of train 'D' = 1440−400 = 1040 meters So, the length of train 'D' is 1040 meters.
The designated partners are liable______.
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