ATQ, Total distance travelled by the trains = 100 + 100 = 200 meters = (200/1000) km = 0.2 km Time taken = (10/3600) hours Let the speed of the slower train be ‘x’ km/hr Speed of the faster train = 2x km/hr Their relative speed = (2x + x) = 3x km/hr According to the question, 
Therefore, the speed of the slower train = 24 km/hr.
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