Question
Two trains, each 100 meters long, are running in
opposite directions. If one train's speed is twice that of the other and they take 10 seconds to cross each other, find the speed of the slower train.Solution
ATQ, Total distance travelled by the trains = 100 + 100 = 200 meters = (200/1000) km = 0.2 km Time taken = (10/3600) hours Let the speed of the slower train be ‘x’ km/hr Speed of the faster train = 2x km/hr Their relative speed = (2x + x) = 3x km/hr According to the question, 
Therefore, the speed of the slower train = 24 km/hr.
More Trains Questions
36895 - 4256 - 2233 = ?
Find the simplified value of the following expression:
[{12 + (13 × 4 ÷ 2 ÷ 2) × 5 – 8} + 13 of 8]
- Simplify:
(21 X 5) + ? = (480 - 120) ÷ 3
What will come in the place of question mark (?) in the given expression?
34 X 11 - ? + 36 = 3 X 75 + 125
- What will come in the place of question mark (?) in the given expression?
(√1089 + 47) X 4.5 = ? - √256 X 10 62 + 43 + 625(1/4) - ? = 102
625 × (?% ÷ 125) = 250% of 10
3 √8 × √36 × 13 = ? × √169
81 ÷ 0.09 × 1.4 – 1223=?
