Two trains, each 140 meters long, are running in opposite directions. If the speed of one train is twice that of the other and they take 18 seconds to cross each other, find the speed of the slower train.(Calculate approximate value)
ATQ, Total distance travelled by the trains = 140 + 140 = 280 meters = 0.28 km Time taken = (18/3600) hours Let the speed of the slower train be ‘x’ km/hr Speed of the faster train = 2x km/hr Their relative speed = (2x + x) = 3x km/hr According to the question, 
Therefore, the speed of the slower train = 18.66 km/hr. or 19 km/hr
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