A 180-metre train takes 9 seconds to cross a pole. If the same train takes 18 seconds to cross train 'D' that is travelling in opposite direction at 14 m/s on a parallel track, then find the length of train 'D'.
ATQ, Speed of train 'A' = (180 ÷ 9) = 20 m/s Let the length of train 'D' be 'x' metres. ATQ; (180 + x) ÷ (20 + 14) = 18 Or, 180 + x = 612 So, 'x' = 612 - 180 = 432 Therefore, length of train 'D' = 432 metres
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