ATQ, Let the speed of the train be ‘x’ m/s. Length of the train = 5 × x = ‘5x’ metres So, length of the platform = (5x + 60) metres ATQ; (5x + 60 + 5x) ÷ 25 = x Or, 10x + 60 = 25x Or, 60 = 15x So, x = 4 Therefore, length of the platform = (4 × 5) + 60 = 80 metres
81% of 2300 – 34% of 550 = ?
25% of 280 × 15% of 460 = ? × 230
150% of ? + 280 ÷ 35 = 132 - 122 + 7
What is the value of 143 + 163 + 183 + … + 303?
? + 156 ÷ 3 × 7 = 35% of 400 + (13)2
44% of 1900 + 25% of ? = 9000
215 + 378 – 23 + 15 - 27 = ? + 3² + 16²
(1296 ÷ 54 × 24 + 24) = ? × 150
72 x 60 x 22 x 32 =?
[(120)2 ÷24 ×25] ÷ 250 =?