ATQ, Let the speed of the train be ‘x’ m/s. Length of the train = 6 × x = ‘6x’ metres So, length of the platform = (6x + 70) metres ATQ; (6x + 70 + 6x) ÷ 18 = x Or, 12x + 70 = 18x Or, 70 = 6x So, x = 11.67 Therefore, length of the platform = (11.67 × 6) + 70 = 140 metres
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