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ATQ, Let the speed of the train be ‘x’ m/s. Length of the train = 6 × x = ‘6x’ metres So, length of the platform = (6x + 70) metres ATQ; (6x + 70 + 6x) ÷ 18 = x Or, 12x + 70 = 18x Or, 70 = 6x So, x = 11.67 Therefore, length of the platform = (11.67 × 6) + 70 = 140 metres
128 ÷ 22 × ? = 15% of 300 ÷ 9
(√1024 + √324)% of 780 = ?% of 260
∛21952 × 44 = ? × 14
154 × 7 + 480 × 5 = ?% of 6956
[(1245 ÷ 9) ÷ 12] × 540 = ?2 – 175
√(24 × 5 ÷ ?) × 4 = 56 + 34 – 10
Find the simplified value of the given expression.
(1/4) of {64 - 28 x 15 + 13 x 16 - 12.5 of 122}
[(√ 529) + 67] x 5 = ?
? % of 1200 = 20% of 30% of 3600
1220 ÷ 61 ÷ 5 + 450 of 20% - 70 = √ ?