Question
A train moves at 90 km/h to
arrive at its station on time. If it moves at 100 km/h, it will arrive 15 minutes earlier. Find the time taken by the train to travel four times the distance at 120 km/h.Solution
ATQ, Let the usual time taken by the train be 'T' hours. Using, distance = speed × time We have, 'D' = 90T ----------- (I) And, 'D' = 100 × {T - (15/60)} -------- (II) From equation (I) and (II), We have, 90T = 100 × {T - (15/60)} Or, 90T = 100T - 100 × (15/60) Or, 10T = 25 Or, 'T' = 2.5 On putting the value of 'T' = 2.5 in equation (I), We have 'D' = 90 × 2.5 = 225 km So, the required time = (4 × 225) ÷ 120 = (900/120) = 7.5 hours
47.87% of 749.76 + 35.11% of 399.76 = √? + 23.15 × 20.87
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What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)...
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