A train travels 240 km at a uniform speed. If the speed of the train is increased by 20 km/h, it takes 1 hour less to cover the same distance. What is the original speed of the train?
Solution: Let the original speed be x km/h. Time taken at original speed = 240/x hours. Time taken at increased speed = 240/(x + 20) hours. According to the problem: 240/x - 240/(x + 20) = 1. Cross-multiplying and simplifying gives: 240(x + 20) - 240x = x(x + 20) => 240 * 20 = x^2 + 20x => x^2 + 20x - 4800 = 0. Using the quadratic formula: x = [-20 ± √(20^2 + 4 * 4800)] / 2 x = 60 km/h. Correct answer: A) 60 km/h
What was the reason for RBI imposing a ₹5,00,000 fine on Aadhar Housing Finance?
Consider the following statements regarding the estimated foodgrain production for 2023-24:
1. The total foodgrain production is estimated at ...
Articles 36 to 51 of the Indian Constitution deal with ___________.
What is the significance of the recently discovered dinosaur Fujianvenator prodigiosus in the context of avian evolution?
Which two Indian states will be connected by India's first bullet train?
The index provider arm of the National Stock Exchange has announced five additions and deletions each to the Nifty Next 50 Index.Apart from the addition...
Five of the top-10 most-valued firms added Rs 1,99,111.06 crore in market valuation last week, with Reliance Industries emerging as the biggest gainer. ...
Consider the following statements about Colombo Security Conclave (CSC):
1. India’s National Security Adviser recently took part in...
________ company has won a contract to build a 300 megawatt (MW) coal fired power plant in Botswana(South Africa).
What distinguishes the realigned AHIDF Scheme launched by Union Minister Parshottam Rupala from its previous version?