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Let speed of train = y m//s So, length of train = 18 × y = 18y metres According to question; (18y + 240) = 30y Or, 12y = 240 Or, y = 20 m/s So, x = 20 × 18/5 = 72 km/h Desired distance = 72 × 15 = 1080 km
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