Speed of train ‘A’ = 54 × (5/18) = 15 m/sec Therefore, length of train ‘A’ = 15 × 12.4 = 186 metres Length of train ‘B’ = 186 + 48 = 234 metres Speed of train ‘B’ = 15 + (15/3) = 20 m/sec Required time taken = (234 + 186)/(15 + 20) = 12 seconds
Statements: N & C, C # I, I @ L, L % Y
Conclusions: I. C & Y II. L # N
...Statements:
E = F > Q = A > B; J < Z ≤ A
Conclusions:
I. Q > Z
II. B ˃ J
Statement: R < P, M < R, D `<=` P = T
Conclusion: I. R > D II. D `>=` M
...Statement: F > E = L ≤ V ≤ P = C
Conclusions:
I. C > E
II. E = C
III. F > P
IV. C ≥ E
...Statements: H > S ≥ F = B ≤ U≤ T; E ≤ B ≤ K
Conclusions:I. K > F II. K = F
Statement: Q > R; O < K ≤ N; O ≥ S > R
Conclusion: I. O ≥ Q II. R < N.
Statements: J < K, J < L, L > M
Conclusions: I. J < M II. L = J
...Statements :
A > B > C
Y > B
D > C > Z
Conclusions :
I. Z > D
II. Y > A
III. B > Z
...Statements: Q > U = V ≤ X; R ≥ S ≥ X
Conclusions:
I. U = S
II. V < S
Statement: F ≥ G > I > E ≤ P, E = S ≥ P
Conclusion: I. F ≥ P II. G > P
