Let the length of the train be 'L' metres and speed of the train be 's' m/s. Speed of the man = 14.4 X (5/18) = 4 m/s ATQ; (L/s) = 12 Or, L = 12s ....... (I) Also, {L/(s - 4)} = 15 Or, 12s = 15 X (s - 4) {Using equation (I)} Or, 12s = 15s - 60 Or, 60 = 3s So, s = 20 So, length of the train = 20 X 12 = 240 metres.
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