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ATQ, Let the length of train P = 'a' m Speed of train P = 'b' Kmph a+350 = b × 5/18 × 42 a+350 = 35b/3 3a+1050 = 35b →1 a = b × 5/18 × 14 9a = 35b → 2 3a+1050 = 9a 6a = 1050 a=175 9a×175 = 35b b = 45Kmph The length of train Q = 175 m 175+175 = (60 - 45)×5/18 × time taken 350 = 15 × 5/18 × time taken Required answer = 84 seconds
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