Question
Train P, which is 300 meters
long, passed train Q moving in the opposite direction toward it in 16 seconds. Train Q took 16.8 seconds to pass a stationary streetlight. Determine how long it will take train P to pass a platform that is 730 meters long, given that train Q took 46 seconds to cross the same platform.Solution
ATQ, Let, length of train Q = βpβ m Speed of train Q = p/16.8 Let, speed of train P = βqβ m/s So, (p + 730)/(p/16.8) = 46 16.8p + 12264 = 46p p = 420 Speed of train Q = 420/16.8 = 25 m/s So, (300 + 420)/(25 + q) = 16 720 = 400 + 16q q = 20 m/s Required time = (730 + 300)/20 = 51.5 seconds
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