Question
A train running with 90km/hr takes 25sec to cross a
platform 250 m long. How much it take to cross a stationary train having length of 75m ?Solution
250+L = 90 × (5/18) × 25 L= 375m 375 + 75 = 90 × (5/18) × t So, t = 18sec.
If asinx +b cosx = c then find the value of acosx - bsinx =?
- If 2 sin x = √3, then the value of x:
A tower is 60 meters high. From a point on the ground, the angle of elevation of the top of the tower is 30°. Find the distance of the point from the b...
If cos3B = sin(0.5B + 6°), then find the measure of 'B'.
If cosec (2A + B) = 2 and cosec (A + B) = 1, find the value of (3A – B).
∆ PQR is right-angled at Q. If ∠R = 60º, then find the value of cosec P.
What is the value of [(tan 5θ + tan 3θ)/4 cos 4θ (tan 5θ – tan 3θ)]?
What is the value of [tan2 (90 – θ) – sin2 (90 – θ)] cosec2 (90 – θ) cot2 (90 – θ)?
...If tan α = 1/2, tan β = 1/3, then find α + β.
Relevant for Exams:
