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Let length of first train be L1& length of 2nd train be L2. So (90+36)×5/18 = (L1+L2)/10 L1+L2 = 350m & L1- L2= 50m Hence L1 = 200m & L2 = 150m i) Already found ii) Already found iii) Time taken by train A to cross a point = 200m/90kmph = 200m/(25m/s) = 8 sec iv) Time taken by train B to cross a platform of length 350m = (350+150)m/36kmph = 500m/(10m/s) = 50 sec Hence all values can be find by given data so correct ans is option (d).
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