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We know that the ratio of the areas of two similar triangles is equal to the square of the ratio of their corresponding sides. Here it is given that ΔABC ~ ΔDEF Given, EF = 15.4 cm Therefore, Area of ΔABC / Area of ΔDEF = (BC)2/(EF)2 64 cm2/ 121 cm2 = (BC)2/(15.4)2 (BC)² = [(15.4)2 × 64]/121 BC = (15.4 × 8)/11 BC = 11.2 cm
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