∠A, ∠B, and∠C are three angles of ∆ABC.if ∠A-∠B=15°, ∠B-∠C =30°,then ∠ A, ∠B and ∠C are?
∠A-∠ B=15° ∠ B-∠ C=30° As we know that ∠A+∠ B+∠ C=180° =15°+∠ B+∠ B+∠ B-30° =180° =3∠B=180°+15°=195° =>∠B=195/3=65°, = ∠A=80° ∠C=35°
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