ABC is an equilateral triangle with sides of 24cm. Find the difference between its in-radius and circum-radius.
In-radius of an equilateral triangle = a√3/6 units where a = side of the equilateral triangle Therefore, the in-radius of the given equilateral triangle = (24√3/6) = 4√3 cm Circum-radius of the given equilateral triangle = 2 × 4√3= 8√3 cm required difference= 8√3cm - 4√3cm= 4√3cm
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